document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36957>Question 36957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22703 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PERIMETER OF A RECTANGLE IS 2*L+2*W THEREFORE 2(2X+2)+2*X=34 OR \r<BR>\n" );
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document.write( "4X+4+2X=34 OR 6X=30 OR X=30/6 OR X=5 PROOF\r<BR>\n" );
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document.write( "4(2*5+2)+2*5=34 OR 4(10+2)+10=34 OR 4*12+10=34 OR 24+10=34 OR 34=34 </SPAN>\n" );
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