document.write( "Question 317038: Find the dimensions of a rectangle of area 225 square centimeters that has the least perimeter. What is the perimeter? \n" ); document.write( "
Algebra.Com's Answer #227009 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
For a rectangle, the area is,
\n" ); document.write( "\"A=L%2AW=225\"
\n" ); document.write( "and the perimeter is,
\n" ); document.write( "\"P=2%28L%2BW%29\"
\n" ); document.write( "From the area equation,
\n" ); document.write( "\"L=225%2FW\"
\n" ); document.write( "Substitute into the P equation,
\n" ); document.write( "\"P=2%28225%2FW%2BW%29=450%2FW%2B2W\"
\n" ); document.write( "Now P is a function of only one variable.
\n" ); document.write( "Take the derivative and set it equal to zero to find extrema.
\n" ); document.write( "\"dP%2FdW=-450%2FW%5E2%2B2=0\"
\n" ); document.write( "\"450%2FW%5E2=2\"
\n" ); document.write( "\"W%5E2=450%2F2=225\"
\n" ); document.write( "\"W=15\"
\n" ); document.write( "\"L=225%2F15=15\"
\n" ); document.write( "The rectangle with the minimum perimeter is a square with side 15 cm.
\n" ); document.write( "\"P=4s=4%2815%29\"
\n" ); document.write( "\"highlight%28P=60%29\" cm.
\n" ); document.write( "
\n" );