document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4771>Question 4771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At Maplewood Marine, shift 1 produced 3 times as much as shift 2.  Maplewood's total production for June was 6,400 row boats.  What was the output for each shift? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2270 by </B><A HREF=/tutors/aboutme.mpl?userid=ichudov><B>ichudov(507)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ichudov><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ichudov><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem says that shift one production is 3 times shift two.\r<BR>\n" );
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document.write( "shift_one_production+shift_two_production=6400\r<BR>\n" );
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document.write( "since shift_one_production = 3* shift_two_production, we have\r<BR>\n" );
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document.write( "3* shift_two_production + shift_two_production = 6400\r<BR>\n" );
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document.write( "4*shift_two_production = 6400.\r<BR>\n" );
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document.write( "shift_two_production = 6400/4 = 1600\r<BR>\n" );
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document.write( "shift_one_production = 1600*3 = 4800.\r<BR>\n" );
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document.write( "You could have used 'x' instead of shift_one_production, the result would be the same. </SPAN>\n" );
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