document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=317021>Question 317021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi all,<BR>\n" );
document.write( "I have a prolem involving converting powers within an Equation:\r<BR>\n" );
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document.write( "As a result of a volcanic eruption, ash began to fall at a rate of:<BR>\n" );
document.write( "(12 Kg) / (m^2 year) \r<BR>\n" );
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document.write( "Transform this quantity into: (g) / (mm^2 month)\r<BR>\n" );
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document.write( "Any help with steps and full working would be great.<BR>\n" );
document.write( "Thanks, -Nick. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226955 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226955\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (12 Kg) / (m^2 year)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "12*1000 = 12000 grams<BR>\n" );
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document.write( "1 m^2 = 1000 mm * 1000 mm<BR>\n" );
document.write( "1 year = 12 months\r<BR>\n" );
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document.write( "..<BR>\n" );
document.write( "12000 / 1000000*12<BR>\n" );
document.write( "=0.001g/mm^2 month </SPAN>\n" );
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