document.write( "Question 316994: find the distance between (-2,9) and (-5,15)\r
\n" ); document.write( "\n" ); document.write( "a)45.02
\n" ); document.write( "b) 6.17
\n" ); document.write( "c)24.18
\n" ); document.write( "d) 18.67
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Algebra.Com's Answer #226920 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=-2\" and \"y%5B1%5D=9\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=-5\" and \"y%5B2%5D=15\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-2--5%29%5E2%2B%289-15%29%5E2%29\" Plug in \"x%5B1%5D=-2\", \"x%5B2%5D=-5\", \"y%5B1%5D=9\", and \"y%5B2%5D=15\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%283%29%5E2%2B%289-15%29%5E2%29\" Subtract \"-5\" from \"-2\" to get \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%283%29%5E2%2B%28-6%29%5E2%29\" Subtract \"15\" from \"9\" to get \"-6\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%289%2B%28-6%29%5E2%29\" Square \"3\" to get \"9\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%289%2B36%29\" Square \"-6\" to get \"36\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2845%29\" Add \"9\" to \"36\" to get \"45\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=3%2Asqrt%285%29\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=3%2Asqrt%285%29\" \r
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\n" ); document.write( "\n" ); document.write( "Which approximates to \"d=6.708\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points is approximately 6.708 units.
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