document.write( "Question 316985: Factor completely:
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Algebra.Com's Answer #226913 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"8z%5E3%2B125\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%282z%29%5E3%2B%285%29%5E3\" Rewrite \"8z%5E3\" as \"%282z%29%5E3\". Rewrite \"125\" as \"%285%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%282z%2B5%29%28%282z%29%5E2-%282z%29%285%29%2B%285%29%5E2%29\" Now factor by using the sum of cubes formula. Remember the sum of cubes formula is \"A%5E3%2BB%5E3=%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282z%2B5%29%284z%5E2-10z%2B25%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So \"8z%5E3%2B125\" factors to \"%282z%2B5%29%284z%5E2-10z%2B25%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"8z%5E3%2B125=%282z%2B5%29%284z%5E2-10z%2B25%29\"
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