document.write( "Question 316878: How do i identify the vertex, focus, and directrix of y=1/12x^2 \n" ); document.write( "
Algebra.Com's Answer #226885 by Fombitz(32388)\"\" \"About 
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The equation is already in vertex form,
\n" ); document.write( "\"y=%281%2F12%29%28x-0%29%5E2%2B0\"
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\n" ); document.write( "The vertex is (0,0).
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\n" ); document.write( "The general equation for a parabola is,
\n" ); document.write( "\"4p%28y-k%29=%28x-h%29%5E2\" where p is the distance from the vertex to the focus.
\n" ); document.write( "In your case,
\n" ); document.write( "\"12%28y-0%29=%28x-0%29%5E2\"
\n" ); document.write( "\"4p=12\"
\n" ); document.write( "\"p=3\"
\n" ); document.write( "The focus is located at (0,0)+(0,3)=(0,3)
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\n" ); document.write( "The directrix is the same distance from the vertex but in the opposite direction.
\n" ); document.write( "\"y=-3\"
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