document.write( "Question 316791: 1) Find two consecutive even numbers such that the difference of one-half of the larger and two-fifths of the smaller is equal to five.\r
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document.write( "2)Find three consecutive numbers such that the sum of one-third of the first and one-seventh of the second is two less that one-half of the third. Help me please. \n" );
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Algebra.Com's Answer #226875 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1) Find two consecutive even numbers such that the difference of one-half of the larger and two-fifths of the smaller is equal to five. \n" ); document.write( "Two consecutive even numbers; x, (x+2), (we can us decimals here 2/5 = .4) \n" ); document.write( ".5(x+2) - .4x = 5 \n" ); document.write( ".5x + 1 - .4x = 5 \n" ); document.write( ".5x - .4x = 5 + 1 \n" ); document.write( ".1x = 4 \n" ); document.write( "x = \n" ); document.write( "x = 40 \n" ); document.write( "40,42 are the numbers \n" ); document.write( ": \n" ); document.write( "Check \n" ); document.write( ".5(42) - .4(40) = \n" ); document.write( "21 - 16 = 5 \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "2)Find three consecutive numbers such that the sum of one-third of the first and one-seventh of the second is two less that one-half of the third \n" ); document.write( "x, (x+1), (x+2) \n" ); document.write( " \n" ); document.write( "Get rid of those annoying fractions, multiply by 42, results: \n" ); document.write( "14x + 6(x+1) = 21(x+2) - 42(2) \n" ); document.write( ": \n" ); document.write( "14x + 6x + 6 = 21x + 42 - 84 \n" ); document.write( ": \n" ); document.write( "20x + 6 = 21x - 42 \n" ); document.write( ": \n" ); document.write( "6 + 42 = 21x - 20x \n" ); document.write( ": \n" ); document.write( "48 = x \n" ); document.write( ": \n" ); document.write( "48, 49, 50 are the three numbers \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( " \n" ); document.write( "16 + 7 = 25 - 2 \n" ); document.write( " \n" ); document.write( " |