document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=316776>Question 316776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me please.  Solve the inequality analytically.<BR>\n" );
document.write( "x square - 2x - 35 < 0\r<BR>\n" );
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document.write( "Thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226730 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 - 2x - 35 = (x-7)(x+5)\r<BR>\n" );
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document.write( "For this to be less than zero, think of the graph which crosses the x-axis at -5 and 7 (where x^2 - 2x - 35 = 0) and between these two points the graph is below the x-axis i.e. negative in value.\r<BR>\n" );
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document.write( "Therefore the range for x^2 - 2x - 35 < 0 is -5 < x < 7 </SPAN>\n" );
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