document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36897>Question 36897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular picture is 12 by 16 inches. if a frame of uniform width contains an area of 165 square inches, what is the width of the frame. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22673 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 165=24X+32X+4X~2 24X IS 2*12*x WHERE X IS THE FRAME WIDTH & 32X IS 2*16*X <BR>\n" );
document.write( "THE 4 COENERS HAVE AREA OF X~2 THUS THE 4X~2 \r<BR>\n" );
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document.write( "165=56X+4X~2 or 4x~2+56x-165=0 OR (2X+33)(2X-5)=0 OR x=5/2 OR 2.5 INCH WIDE \r<BR>\n" );
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document.write( "FRAME  </SPAN>\n" );
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