document.write( "Question 316473: the perimeter of a right triangle is 60 cm & its hypotenuse is 26 cm. find the other two sides & the area of the triangle. \n" ); document.write( "

Algebra.Com's Answer #226701 by Fombitz(32388) $\"\"$ $\"About$

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$\"A%2BB%2B26=60\"$
\n" ); document.write( "1. $\"A%2BB=34\"$
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\n" ); document.write( " $\"A%5E2%2BB%5E2=26%5E2\"$
\n" ); document.write( "2. $\"A%5E2%2BB%5E2=676\"$
\n" ); document.write( "From eq. 1,
\n" ); document.write( " $\"A=34-B\"$
\n" ); document.write( " $\"A%5E2=1156-68B%2BB%5E2\"$
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( " $\"%281156-68B%2BB%5E2%29%2BB%5E2=676\"$
\n" ); document.write( " $\"2B%5E2-68B%2B480=0\"$
\n" ); document.write( " $\"B%5E2-34B%2B240=0\"$
\n" ); document.write( " $\"%28B-24%29%28B-10%29=0\"$
\n" ); document.write( "Two solutions:
\n" ); document.write( " $\"B-24=0\"$
\n" ); document.write( " $\"B=24\"$
\n" ); document.write( "Then
\n" ); document.write( " $\"A%2B24=34\"$
\n" ); document.write( " $\"A=10\"$
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\n" ); document.write( " $\"B-10=0\"$
\n" ); document.write( " $\"B=10\"$
\n" ); document.write( "Then
\n" ); document.write( " $\"A%2B10=34\"$
\n" ); document.write( " $\"A=24\"$
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\n" ); document.write( "Area= $\"%281%2F2%29bh=%281%2F2%29%2824%29%2810%29=120\"$ \n" ); document.write( "

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