document.write( "Question 36879: Sue has $3.50 of dimes and nickels. If she has 50 coins, how many of each type of coin does she have? \n" ); document.write( "
Algebra.Com's Answer #22670 by checkley71(8403)\"\" \"About 
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350=10X+5(50-X) OR 350=10X+250-5X OR 100=5X OR X-100/5 OR X=20 DIMES THUS WE HAVE 50-20=30 NICKELS.
\n" ); document.write( "PROOF 10*20+5*30=350 OR 200+150=350 OR 350=350
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