document.write( "Question 36889: The combined cost of one advance ticket to a show and one same-day ticket was $55 . It is known that 30 tickets were sold in advance and 25 the same day, for total receipts of $1575 . What was the price of each kind of ticket?
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Algebra.Com's Answer #22669 by stanbon(75887)\"\" \"About 
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The combined cost of one advance ticket to a show and one same-day ticket was $55 . It is known that 30 tickets were sold in advance and 25 the same day, for total receipts of $1575 . What was the price of each kind of ticket? \r
\n" ); document.write( "\n" ); document.write( "Let cost of advance tickets be \"x\"
\n" ); document.write( "Then cost of same day tickets is \"55-x\"
\n" ); document.write( "Value of advance tickets sold is 30x
\n" ); document.write( "Value of same day tickets sold is 25(55-x)
\n" ); document.write( "EQUATION:
\n" ); document.write( "Value + Value = $1575
\n" ); document.write( "30x+25(55-x)=1575
\n" ); document.write( "30x+(25)(55)-25x=1575
\n" ); document.write( "5x=1575-25(55)
\n" ); document.write( "x=315-275
\n" ); document.write( "x=$40 (price of advance tickets)
\n" ); document.write( "55-x=$15 (price of same day tickets)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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