document.write( "Question 316708: Mike and Jon leave their homes at the same time and meet somewhere in between their homes. Mike leaves and walks 2 meters per second. Jon walks 2.5 meters per second. If their homes are 20 meters apart, how far from jons house will they meet. How long did each walk? \n" ); document.write( "
Algebra.Com's Answer #226681 by mananth(16946) You can put this solution on YOUR website! speed ofmike = 2m/sec \n" ); document.write( "speed of jon 2.5 m/sec \n" ); document.write( ".. \n" ); document.write( "let them meet x m from jon's place \n" ); document.write( "so mike has walked 20-x m \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "time taken by mike = 20-x / 2 \n" ); document.write( "time taken by jon = x/2.5 \n" ); document.write( ".. \n" ); document.write( "these times are same. \n" ); document.write( "20-x /2 = x / 2.5 \n" ); document.write( "2.5(20-x)=2x \n" ); document.write( "50-2.5x=2x \n" ); document.write( "50=4.5x \n" ); document.write( "x=11.1 m distance from jon's place \n" ); document.write( "mike walks 9.9 meters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |