document.write( "Question 316567: 12/5x+7=31-3/5x
\n" ); document.write( "-2x+5x-9=3(x-4)-5
\n" ); document.write( "-5/6x=-15
\n" ); document.write( "6=x/7
\n" ); document.write( "4/5x=-15
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Algebra.Com's Answer #226677 by rfer(16322)\"\" \"About 
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12/5x+7=31-3/5x
\n" ); document.write( "15/5x=24
\n" ); document.write( "5x=1.6
\n" ); document.write( "x=0.32
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