document.write( "Question 36889: The combined cost of one advance ticket to a show and one same-day ticket was $55 . It is known that 30 tickets were sold in advance and 25 the same day, for total receipts of $1575 . What was the price of each kind of ticket?
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Algebra.Com's Answer #22666 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 30X+25(55-X)=1575 OR 30X+1375-25X=1575 OR 5X=200 OR X=200/5 OR X=40 TICKETS SOLD FOR $30 EACH & 55-40=15 TICKETS SOLD FOR $25\r \n" ); document.write( "\n" ); document.write( "PROOF 30*40+15*25=1575 OR 1200+375=1575 OR 1575=1575 \n" ); document.write( " |