document.write( "Question 316596: barry invested $2000, part at 8% annum and the rest at 10% annum. After one year the total interest earned was $190. How much did he invest at each rate?
\n" ); document.write( "please help, i have my exam tomorrow and i lost my note on this,
\n" ); document.write( "

Algebra.Com's Answer #226640 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
amount invested @ 8 % be x
\n" ); document.write( "amount invested @10% will be 2000-x
\n" ); document.write( "..
\n" ); document.write( "interest equation
\n" ); document.write( "0.08x+0.1(2000-x)=190
\n" ); document.write( "0.08x + 200-0.1x=190
\n" ); document.write( "-0.02x=-10
\n" ); document.write( "x=-10/-0.02
\n" ); document.write( "x=500
\n" ); document.write( "$500 at 8%
\n" ); document.write( "balance $ 1500 @ 10%
\n" ); document.write( "..
\n" ); document.write( "CHECK
\n" ); document.write( "1500@10% = 150
\n" ); document.write( "500@8%=40
\n" ); document.write( "TOtal = 190
\n" ); document.write( "
\n" );