document.write( "Question 316631: If a boat travels downstream for one hour and travels twelve miles and returns upstream to the starting point and the trip requires four hours how fast is the current \n" ); document.write( "
Algebra.Com's Answer #226636 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If a boat travels downstream for one hour and travels twelve miles and returns \n" ); document.write( " upstream to the starting point and the trip requires four hours how fast is the current \n" ); document.write( ": \n" ); document.write( "Let s = speed of boat in still water \n" ); document.write( "Let c = speed of the current \n" ); document.write( ": \n" ); document.write( "Write a distance equation for each trip: \n" ); document.write( "1(s + c) = 12 \n" ); document.write( "4(s - c) = 12 \n" ); document.write( ": \n" ); document.write( "Simplify the second equation; divide by 4, subtract from the 1st equation \n" ); document.write( "s + c =12 \n" ); document.write( "s - c = 3 \n" ); document.write( "-----------subtraction eliminates s, find c \n" ); document.write( " 2c = 9 \n" ); document.write( "c = \n" ); document.write( "c = 4.5 mph is the current \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution, find the speed of the boat \n" ); document.write( "s + 4.5 = 12 \n" ); document.write( "s = 12 - 4.5 \n" ); document.write( "s = 7.5 mph speed of the boat \n" ); document.write( "Check solution in the return equation \n" ); document.write( "4(7.5 - 4.5) = \n" ); document.write( "4(3) = 12 \n" ); document.write( " |