document.write( "Question 316685: in a shipment of 15 sets of golf clubs, 3 are left handed. if 4 sets of golf clubs are selected, what is the proability that exactily 1 is left handed, at least 1 is left-handed, no more than 2 are left handed and what is the eman number of left handed sets of golf clubs that you would expect to find in th esmaple of 4 sets of golf clubs \n" ); document.write( "
Algebra.Com's Answer #226615 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! in a shipment of 15 sets of golf clubs, 3 are left handed. \n" ); document.write( "if 4 sets of golf clubs are selected, \n" ); document.write( "--- \n" ); document.write( "Binomial Problem with n = 4 ; p = 1/5 \n" ); document.write( "---------- \n" ); document.write( "what is the proability that \n" ); document.write( "exactly 1 is left handed = 4C1(1/5)(4/5)^3 = 0.4096 \n" ); document.write( "---------- \n" ); document.write( "at least 1 is left-handed = 1 - P(x=0) = 1-(4/5)^4 = 0.5904 \n" ); document.write( "---------- \n" ); document.write( "no more than 2 are left handed = binomcdf(4,1/5,2) = 0.9728 \n" ); document.write( "---------------------- \n" ); document.write( "what is the mean number of left handed sets of golf clubs that you would expect to find in the sample of 4 sets of golf clubs:::np = 4*(1/5) = 4/5 \n" ); document.write( "--------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================================ \n" ); document.write( " \n" ); document.write( " |