document.write( "Question 316538: A bicycle leaves town at 10 mph at 8 am. A car leaves town going the same direction at 11am going 50 mph. How many minutes after 11 am will it be when the car overtakes the bicycle? \n" ); document.write( "
Algebra.Com's Answer #226611 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "D=10T FOR THE BICYCLE.
\n" ); document.write( "D=50(T-3) FOR THE CAR.
\n" ); document.write( "10T=50(T-3)
\n" ); document.write( "10T=50T-150
\n" ); document.write( "10T-50T=-150
\n" ); document.write( "-40T=-150
\n" ); document.write( "T=-150/-40
\n" ); document.write( "T=15/4=3.75 TRAVEL TIME FOR THE BICYCLE.
\n" ); document.write( "3.75-3=.75 TRAVEL TIME FOR THE CAR.
\n" ); document.write( "PROOF:
\n" ); document.write( "10*3.75=50*.75
\n" ); document.write( "37.5=37.5
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