document.write( "Question 316658: How much money will there be in the account after the given number of years for the following\r
\n" ); document.write( "\n" ); document.write( "P=$4,000 r= 4.5% COMPOUNDED MONTHLY, t= 3 years
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Algebra.Com's Answer #226590 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Compound interest formula:
\n" ); document.write( "\"A+=+P%281+%2B+i%2Fn%29%5E%28nt%29\"
\n" ); document.write( "Where
\n" ); document.write( "A is amount after time t
\n" ); document.write( "P is the principal
\n" ); document.write( "i is the interest
\n" ); document.write( "n is number of times compounded
\n" ); document.write( "t is time (in years)
\n" ); document.write( ".
\n" ); document.write( "\"A+=+P%281+%2B+i%2Fn%29%5E%28nt%29\"
\n" ); document.write( "Plug in what was given:
\n" ); document.write( "\"A+=+4000%281+%2B+.045%2F12%29%5E%2812%2A3%29\"
\n" ); document.write( "\"A+=+4000%281+%2B+.00375%29%5E%2836%29\"
\n" ); document.write( "\"A+=+4000%281.00375%29%5E36\"
\n" ); document.write( "A = $4,576.99
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