document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=316669>Question 316669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The period T(time in seconds for one complete cycle) of a simple pendulum is related to the length L (in feet) of the pendulum by the formula 8T^2=pi^2L. If a child is on a swing with a 10-foot chain, then how long does it take to complete one cycle of the swing? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226588 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8T^2=pi^2L<BR>\n" );
document.write( "8t^2=9.86*10<BR>\n" );
document.write( "8t^2=98.6<BR>\n" );
document.write( "t^2=98.6/8<BR>\n" );
document.write( "t^2=12.345<BR>\n" );
document.write( "t=sqrt12.345<BR>\n" );
document.write( "t=3.51 seconds. </SPAN>\n" );
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