document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36883>Question 36883</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A child in an airport is able to cover 392 meters in 4 minutes running at a steady speed down a moving sidewalk in the direction of the sidewalk's motion. Running at the same speed in the direction opposite to the sidewalk's movement, the child is able to cover 204  meters in 3  minutes. What is the child's running speed on a still sidewalk, and what is the speed of the moving sidewalk? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22658 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22658\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 392/4=98 & 204/3=68 OR (98-68)/2= 30/2=15 METERS PER MIN IS THE SPEED OF THE SIDEWALK &\r<BR>\n" );
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document.write( "CHILD'S SPEED IS 98-15=83 METERS/MIN OR 68+15=83 METERS/MIN  </SPAN>\n" );
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