document.write( "Question 316628: if you are 1500 feet from a very tall tower and look up at a 45 degree angle to see the top how tall is the tower \n" ); document.write( "

Algebra.Com's Answer #226565 by Edwin McCravy(20056) $\"\"$ $\"About$

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if you are 1500 feet from a very tall tower and look up at a 45 degree angle to see the top how tall is the tower?\r
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document.write( "Since there is a 90° angle and a 45° angle, the third angle is\r\n" );
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document.write( "180° - (90° + 45°) = 180° - 135° = 45°\r\n" );
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document.write( "So the triangle has two congruent acute angles and so it is\r\n" );
document.write( "an isosceles right triangle.  That means both legs have the same\r\n" );
document.write( "measure, and since we are given that the horizontal leg is 1500 \r\n" );
document.write( "feet, the vertical leg, which is the tower, is also 1500 feet.\r\n" );
document.write( "Notice that an isosceles right triangle (often called a 45-45-90\r\n" );
document.write( "triangle) is one-half of a square cut down the diagonal, as you\r\n" );
document.write( "can see from the drawing below:\r\n" );
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document.write( "Edwin

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