document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=316648>Question 316648</A>: <I><SPAN STYLE=\"word-break: break-all;\">  i am having a lot of trouble with my relations and functions assignment i have made the first two problems a succes after various tries, but the third is a little trickier will you please help... and show steps.(f(x)= (-11))\r<BR>\n" );
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document.write( "3. F(-11)= (-4+7(-11))/(5+5(-11)^2+5(-11))\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226544 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Apply the \"order of operations\" -- PEMDAS (Please Excuse My Dear Aunt Sally) refers to:<BR>\n" );
document.write( "Parentheses<BR>\n" );
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document.write( "Multiplication/division -- right to left<BR>\n" );
document.write( "Addition/subtraction -- right to left<BR>\n" );
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document.write( "F(-11)= (-4+7(-11))/(5+5(-11)^2+5(-11))<BR>\n" );
document.write( "F(-11)= (-4+7(-11))/(5+5(121)+5(-11))<BR>\n" );
document.write( "F(-11)= (-4-77)/(5+5(121)+5(-11))<BR>\n" );
document.write( "F(-11)= (-4-77)/(5+605+5(-11))<BR>\n" );
document.write( "F(-11)= (-4-77)/(5+605-55)<BR>\n" );
document.write( "F(-11)= -81/(5+605-55)<BR>\n" );
document.write( "F(-11)= -81/(610-55)<BR>\n" );
document.write( "F(-11)= -81/555<BR>\n" );
document.write( "F(-11)= -27/185 (this would be the simplified fraction form)<BR>\n" );
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document.write( "F(-11)= -.14595 (or, this would be the approx decimal form)\r<BR>\n" );
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