document.write( "Question 36872: m/m^2-m-12 + 5/m+3\r
\n" ); document.write( "\n" ); document.write( "This is what i came up with but i'm not exactly sure how i got it. I'm not sure how to get the denominators the same. Please walk me through this problem step by step. Thank you. I don't have a text book. My instructor gives us problems from his book.\r
\n" ); document.write( "\n" ); document.write( "5(m-4)/m+3(m+3)(m-4)
\n" ); document.write( "m+5m-20\r
\n" ); document.write( "\n" ); document.write( "answer =
\n" ); document.write( "6m-20/m^2-m-12 \n" ); document.write( "
Algebra.Com's Answer #22652 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
m/m^2-m-12 + 5/m+3
\n" ); document.write( "=m/[(m-4)(m+3)] + 5/(m+3)\r
\n" ); document.write( "\n" ); document.write( "The LCD = (m-4)(m+3)
\n" ); document.write( "Rewrite each fraction with this LCD is its denominator, as follows:
\n" ); document.write( "= m/LCD + 5(m-4)/LCD
\n" ); document.write( "Now add the fractions to get:
\n" ); document.write( "=[m+5(m-4)]/LCD
\n" ); document.write( "Simplify as much as possible, as follows:
\n" ); document.write( "=[6m-20]/[(m-4)(m+3)]\r
\n" ); document.write( "\n" ); document.write( "Your answer is correct.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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