document.write( "Question 316542: a motor boat maintained speed of 27 miles per hour relative to the water going 20 miles upstream and returning. The total time of the trip was 1.5 hours. What is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #226516 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a motor boat maintained speed of 27 miles per hour relative to the water going 20 miles upstream and returning. \n" ); document.write( " The total time of the trip was 1.5 hours. What is the speed of the current? \n" ); document.write( ": \n" ); document.write( "Let c = speed of the current \n" ); document.write( "then \n" ); document.write( "(27-c) = effective speed upstream \n" ); document.write( "and \n" ); document.write( "(27+c) = effective speed downstream \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "Time up + time down = 1.5 hrs \n" ); document.write( " \n" ); document.write( "Multiply equation by (27-c)(27+c), results \n" ); document.write( "20(27+c) + 20(27-c) = 1.5(27-c)(27+c) \n" ); document.write( ": \n" ); document.write( "540 + 20c + 540 - 20c = 1.5(729-c^2) \n" ); document.write( ": \n" ); document.write( "1080 = 1093.5 - 1.5c^2 \n" ); document.write( ": \n" ); document.write( "1.5c^2 = 1093.5 - 1080 \n" ); document.write( ": \n" ); document.write( "1.5c^2 = 13.5 \n" ); document.write( "c^2 = \n" ); document.write( "c^2 = 9 \n" ); document.write( "c = \n" ); document.write( "c = 3 mph is the speed of the current \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that's true, find the time of each \n" ); document.write( "20/30 = .67 \n" ); document.write( "20/24 = .83 \n" ); document.write( "------------- \n" ); document.write( "totals:1.5 hrs \n" ); document.write( " |