document.write( "Question 316598: The XYZ Company tested a new product and found its lifetime to be normally distributed, with a mean life of 146 days and a standard deviation of 19.5 days. what is the probability that a product will last between 154 and 180 days? \n" ); document.write( "
Algebra.Com's Answer #226503 by stanbon(75887) ![]() You can put this solution on YOUR website! The XYZ Company tested a new product and found its lifetime to be normally distributed, with a mean life of 146 days and a standard deviation of 19.5 days. what is the probability that a product will last between 154 and 180 days? \n" ); document.write( "-------------- \n" ); document.write( "Find the z-values: \n" ); document.write( "z(154) = (154-146)/19.5 = 0.4103 \n" ); document.write( " --- \n" ); document.write( "z(180) = (180-146)/19.5 = 1.7436 \n" ); document.write( "------------------------------------- \n" ); document.write( "P(154 < x < 180) = P(0.4103 < z < 1.7436) = 0.3002 \n" ); document.write( "======================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |