document.write( "Question 316598: The XYZ Company tested a new product and found its lifetime to be normally distributed, with a mean life of 146 days and a standard deviation of 19.5 days. what is the probability that a product will last between 154 and 180 days? \n" ); document.write( "
Algebra.Com's Answer #226503 by stanbon(75887)\"\" \"About 
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The XYZ Company tested a new product and found its lifetime to be normally distributed, with a mean life of 146 days and a standard deviation of 19.5 days. what is the probability that a product will last between 154 and 180 days?
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\n" ); document.write( "Find the z-values:
\n" ); document.write( "z(154) = (154-146)/19.5 = 0.4103
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\n" ); document.write( "z(180) = (180-146)/19.5 = 1.7436
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\n" ); document.write( "P(154 < x < 180) = P(0.4103 < z < 1.7436) = 0.3002
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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