document.write( "Question 316528: The sum of 2 numbersa is 41. The larger number is more than 4 times the smaller number. What are these numbers \n" ); document.write( "

Algebra.Com's Answer #226500 by moshiz08(60) $\"\"$ $\"About$

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Call the two numbers x and y. Let's say x is larger than y. \r
\n" ); document.write( "\n" ); document.write( "The larger number, x, is 4 times the smaller number, y. Written as an equation this says $\"+x+=+4%2Ay\"$ . \r
\n" ); document.write( "\n" ); document.write( "The sum is 41, so $\"+x+%2B+y+=+41\"$ .Now we can substitute our equation for x into this one. \r
\n" ); document.write( "\n" ); document.write( " $\"+x+%2B+y+=+41\"$
\n" ); document.write( " $\"+4%2Ay+%2B+y+=+41\"$
\n" ); document.write( " $\"+5y+=+41+\"$
\n" ); document.write( " $\"y+=+41%2F5+=+8.2+\"$ \r
\n" ); document.write( "\n" ); document.write( "Then $\"x+=+4%2Ay+=+4+%2A+8.2=+32.8\"$ . \r
\n" ); document.write( "\n" ); document.write( "Now we can check: indeed, the larger number 32.8 is 4 times the smaller number 8.2. When you add them, 32.8 + 8.2, you get 41, so this checks. \n" ); document.write( "

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