document.write( "Question 316580: A tourist can bicycle 52 miles in the same time as he can walk 20 miles. If he can ride 8 mph faster than he can walk, how much time should he allow to walk a 29 mile trail? (Hint: How fast can he walk?) \n" ); document.write( "
Algebra.Com's Answer #226481 by texttutoring(324)\"\" \"About 
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We need to use the formula D=VT, where D=distance, V=velocity (or speed) and T=time\r
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\n" ); document.write( "\n" ); document.write( "I will use subscript b for biking, and w for walking:\r
\n" ); document.write( "\n" ); document.write( "Db = 52 miles
\n" ); document.write( "Dw = 20 miles
\n" ); document.write( "Vb = Vw +8\r
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\n" ); document.write( "\n" ); document.write( "The times are the same, so isolate for T in the D=VT equation:\r
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\n" ); document.write( "\n" ); document.write( "Tw = Dw/Vw
\n" ); document.write( "Tb = Db/Vb\r
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\n" ); document.write( "\n" ); document.write( "Now set Tb and Tw equal to each other:\r
\n" ); document.write( "\n" ); document.write( "Db/(Vw+8) = 20/Vw\r
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\n" ); document.write( "\n" ); document.write( "Cross multiply and solve for Vw:\r
\n" ); document.write( "\n" ); document.write( "52*Vw = 20*Vw +160
\n" ); document.write( "32*Vw = 160
\n" ); document.write( "Vw = 5\r
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\n" ); document.write( "\n" ); document.write( "So the man's walking speed is 5 mph.\r
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\n" ); document.write( "\n" ); document.write( "To find the time to walk a 29 mile trail, use T=D/V\r
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\n" ); document.write( "\n" ); document.write( "T = 29 / 5
\n" ); document.write( "T=5.8\r
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\n" ); document.write( "\n" ); document.write( "He should allow 5.8 hours to walk a 29 mile trail.
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