document.write( "Question 316580: A tourist can bicycle 52 miles in the same time as he can walk 20 miles. If he can ride 8 mph faster than he can walk, how much time should he allow to walk a 29 mile trail? (Hint: How fast can he walk?) \n" ); document.write( "
Algebra.Com's Answer #226481 by texttutoring(324)![]() ![]() You can put this solution on YOUR website! We need to use the formula D=VT, where D=distance, V=velocity (or speed) and T=time\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I will use subscript b for biking, and w for walking:\r \n" ); document.write( "\n" ); document.write( "Db = 52 miles \n" ); document.write( "Dw = 20 miles \n" ); document.write( "Vb = Vw +8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The times are the same, so isolate for T in the D=VT equation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Tw = Dw/Vw \n" ); document.write( "Tb = Db/Vb\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now set Tb and Tw equal to each other:\r \n" ); document.write( "\n" ); document.write( "Db/(Vw+8) = 20/Vw\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cross multiply and solve for Vw:\r \n" ); document.write( "\n" ); document.write( "52*Vw = 20*Vw +160 \n" ); document.write( "32*Vw = 160 \n" ); document.write( "Vw = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the man's walking speed is 5 mph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To find the time to walk a 29 mile trail, use T=D/V\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "T = 29 / 5 \n" ); document.write( "T=5.8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "He should allow 5.8 hours to walk a 29 mile trail. \n" ); document.write( " |