document.write( "Question 316581: A bookstore can purchase several calculators for a total cost of $216. If each calculator cost $2 less, the bookstore could purchase 9 additional calculators at the same total cost. How many calculators, n, can be purchased at the regular price? \n" ); document.write( "
Algebra.Com's Answer #226479 by texttutoring(324)\"\" \"About 
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Let n = number of calculators
\n" ); document.write( "Let p = original price of calculators\r
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\n" ); document.write( "\n" ); document.write( "You have two variables, so you need two equations:\r
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\n" ); document.write( "\n" ); document.write( "Equation 1: 216 = np
\n" ); document.write( "Equation 2: 216 = (n+9)(p-2)\r
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\n" ); document.write( "\n" ); document.write( "Isolate for n in Equation 1: n = 216/p\r
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\n" ); document.write( "\n" ); document.write( "Now plug this value into Equation 2 and solve for p:\r
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\n" ); document.write( "\n" ); document.write( "216 =(216/p + 9)(p-2)\r
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\n" ); document.write( "\n" ); document.write( "Do FOIL:\r
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\n" ); document.write( "\n" ); document.write( "216 = 216 + 9p -432/p -18
\n" ); document.write( "0 = 9p -432/p -18\r
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\n" ); document.write( "\n" ); document.write( "Multiply everything by p:\r
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\n" ); document.write( "\n" ); document.write( "0 = 9p^2 -18p -432
\n" ); document.write( "0 = 9(p^2 -2p -48)
\n" ); document.write( "0 = 9(p-8)(p+6)\r
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\n" ); document.write( "\n" ); document.write( "So either p=8 or p=-6. We have to choose the positive value, because a negative price wouldn't make sense.\r
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\n" ); document.write( "\n" ); document.write( "Now let's solve for n:\r
\n" ); document.write( "\n" ); document.write( "n=216/p
\n" ); document.write( "n=216/8
\n" ); document.write( "n=27\r
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\n" ); document.write( "\n" ); document.write( "So 27 calculators can be purchased at the regular price of $8 each.
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