document.write( "Question 316559: You invested a total of $5000.00 in 2 different banks. One bank pays 4% interest, and the other bank pays 6.5% interest. If you earn a total of $282.50 in interest the first year, how much did you invest in each bank? \n" ); document.write( "
Algebra.Com's Answer #226475 by texttutoring(324)![]() ![]() You can put this solution on YOUR website! Let x = amount invested at 4% \n" ); document.write( "Let y = amount invested at 6.5%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You have two variables, so you need two equations:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation 1: x+y = 5000 (the sum of money invested was $5000) \n" ); document.write( "Equation 2: 0.04x + 0.065y = 282.50 (the sum of the interest earned)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Isolate for one of the variables in Equation 1, then plug it into Equation 2. I will choose to isolate for x:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 5000-y\r \n" ); document.write( "\n" ); document.write( "0.04(5000-y) + 0.065y =282.50 \n" ); document.write( "200-0.04y +0.065y = 282.50 \n" ); document.write( "0.025y = 82.50 \n" ); document.write( "y=3300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x =5000-y \n" ); document.write( "x=1700\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So $1700 was invested at 4% and $3300 was invested at 6.5%. \n" ); document.write( " |