document.write( "Question 36868: -6x+9>3\r
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Algebra.Com's Answer #22647 by martinr(6)\"\" \"About 
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-6x + 9 > 3. You need to solve for x and then graph the solution on the numberline. You can identify whether the point on the line is a solid or an open circle. Since the inequality symbol is Greater than, the circle is open (not filled in). In order to be a closed cirlce, the inequality needs to also be EQUAL TO.
\n" ); document.write( "First, subtract 9 from both sides.
\n" ); document.write( "Next, divide by -6. ** When you multiply or divide with a negative, then you need to reverse the inquality symbol.\r
\n" ); document.write( "\n" ); document.write( "-6x + 9 > 3
\n" ); document.write( " - 9 -9
\n" ); document.write( "-6x > -6
\n" ); document.write( "Divide with a -6
\n" ); document.write( "x < 1 Switch the inequality symbol.
\n" ); document.write( "On a number line, put an open circle @ 1, and shade to the left of 1.\r
\n" ); document.write( "\n" ); document.write( "<-------0
\n" ); document.write( "-2 -1 0 1 2 3
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