document.write( "Question 316556: The width of a rectangle is 3 meters less than the length.The perimeter is 14 meters.Find the width.\r
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\n" ); document.write( "\n" ); document.write( "The second angle of a triangle is twice the first angle.The third angle is 20
\n" ); document.write( "degrees more than the first angle.Find the first angle.
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Algebra.Com's Answer #226460 by texttutoring(324)\"\" \"About 
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Let w=width
\n" ); document.write( "Let l=length\r
\n" ); document.write( "\n" ); document.write( "The width is 3 metres less than the length:\r
\n" ); document.write( "\n" ); document.write( "w = l - 3\r
\n" ); document.write( "\n" ); document.write( "or, l = w+3\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle is given by: P=2w+2l\r
\n" ); document.write( "\n" ); document.write( "Plug l=w+3 into the perimeter equation and solve for w:\r
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\n" ); document.write( "\n" ); document.write( "P=2w+2l
\n" ); document.write( "P=2w + 2(w+3)
\n" ); document.write( "14 = 2w + 2w +6
\n" ); document.write( "8 = 4w
\n" ); document.write( "w = 2\r
\n" ); document.write( "\n" ); document.write( "The length is l = w+ 3 = 2+3 = 5.\r
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\n" ); document.write( "\n" ); document.write( "Angle question:\r
\n" ); document.write( "\n" ); document.write( "Let a=first angle, b=2nd angle, c=3rd angle\r
\n" ); document.write( "\n" ); document.write( "b=2a
\n" ); document.write( "c=a+20\r
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\n" ); document.write( "\n" ); document.write( "All triangles must have angle sums of 180 degrees, so:\r
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\n" ); document.write( "\n" ); document.write( "a+b+c = 180\r
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\n" ); document.write( "\n" ); document.write( "Now plug in b=2a and c=a+20 into this equation:\r
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\n" ); document.write( "\n" ); document.write( "a+b+c=180
\n" ); document.write( "a + 2a + a+20 = 180
\n" ); document.write( "4a + 20 = 180
\n" ); document.write( "4a = 160
\n" ); document.write( "a = 40\r
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\n" ); document.write( "\n" ); document.write( "The first angle is 40 degrees.
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