document.write( "Question 316552: Idk how to solv this
\n" ); document.write( "13x-2y=70
\n" ); document.write( "2x-2y=4
\n" ); document.write( "Its substituting \n" ); document.write( "

Algebra.Com's Answer #226452 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
(1) $\"13x-2y=70\"$
\n" ); document.write( "(2) $\"2x-2y=4\"$
\n" ); document.write( "Divide both sides of (2) by $\"2\"$
\n" ); document.write( "(2) $\"x+-+y+=+2\"$
\n" ); document.write( "Add $\"y\"$ to both sides
\n" ); document.write( "(2) $\"x+=+y+%2B+2\"$
\n" ); document.write( "Substitute this value for $\"x\"$ in (1)
\n" ); document.write( "(1) $\"13%2A%28y+%2B+2%29+-+2y+=+70\"$
\n" ); document.write( "(1) $\"13y+%2B+26+-+2y+=+70\"$
\n" ); document.write( "Subtract $\"26\"$ from both sides
\n" ); document.write( "(1) $\"11y+=+70+-+26\"$
\n" ); document.write( "(1) $\"11y+=+44\"$
\n" ); document.write( "(1) $\"y+=+4\"$
\n" ); document.write( "Now substitute this into (2)
\n" ); document.write( "(2) $\"2x+-+2%2A4+=+4\"$
\n" ); document.write( "Add $\"8\"$ to both sides
\n" ); document.write( "(2) $\"2x+=+4+%2B+8\"$
\n" ); document.write( "(2) $\"2x+=+12\"$
\n" ); document.write( "(2) $\"x+=+6\"$
\n" ); document.write( "The solution is x = 6 and y = 4 \n" ); document.write( "

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