document.write( "Question 316552: Idk how to solv this
\n" ); document.write( "13x-2y=70
\n" ); document.write( "2x-2y=4
\n" ); document.write( "Its substituting
\n" ); document.write( "

Algebra.Com's Answer #226450 by CharlesG2(834)\"\" \"About 
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I do not know how to solve this
\n" ); document.write( "13x-2y=70
\n" ); document.write( "2x-2y=4
\n" ); document.write( "Its substituting\r
\n" ); document.write( "\n" ); document.write( "13x - 2y = 70
\n" ); document.write( " 2x - 2y = 4 (using elimination so I am multiplying this by -1 and adding to the above line to cancel out the y)\r
\n" ); document.write( "\n" ); document.write( " 11x + 0y = 66 --> x = 6
\n" ); document.write( "-2x + 2y = -4\r
\n" ); document.write( "\n" ); document.write( "-2(6) + 2y = -4
\n" ); document.write( "-12 + 2y = -4
\n" ); document.write( "2y = 8
\n" ); document.write( "y = 4\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "13(6) - 2(4) = 78 - 8 = 70
\n" ); document.write( " 2(6) - 2(4) = 12 - 8 = 4 \r
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