document.write( "Question 316552: Idk how to solv this
\n" ); document.write( "13x-2y=70
\n" ); document.write( "2x-2y=4
\n" ); document.write( "Its substituting \n" ); document.write( "

Algebra.Com's Answer #226448 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
1. $\"13x-2y=70\"$
\n" ); document.write( "2. $\"2x-2y=4\"$
\n" ); document.write( "From eq. 2,
\n" ); document.write( " $\"2y=2x-4\"$
\n" ); document.write( "Substitute into eq. 1
\n" ); document.write( " $\"13x-2y=70\"$
\n" ); document.write( " $\"13x-%282x-4%29=70\"$
\n" ); document.write( " $\"11x%2B4=70\"$
\n" ); document.write( " $\"11x=66\"$
\n" ); document.write( " $\"highlight%28+x=6%29\"$
\n" ); document.write( "Then use eq. 2 to find $\"y\"$ .
\n" ); document.write( " $\"2y=2x-4\"$
\n" ); document.write( " $\"2y=2%286%29-4\"$
\n" ); document.write( " $\"2y=12-4=8\"$
\n" ); document.write( " $\"highlight%28+y=4%29\"$ \n" ); document.write( "

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