document.write( "Question 316537: What is the perimeter of a 45°-45°-90° triangle with a hypotenuse length of 28 feet? (Please round to the nearest whole number.)
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Algebra.Com's Answer #226440 by CharlesG2(834)\"\" \"About 
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What is the perimeter of a 45°-45°-90° triangle with a hypotenuse length of 28 feet? (Please round to the nearest whole number.) \r
\n" ); document.write( "\n" ); document.write( "tan 45 = opposite/adjacent = 1
\n" ); document.write( "cos 45 = adjacent/hypotenuse = 1/hyp
\n" ); document.write( "sin 45 = opposite/hypotenuse = 1/hyp
\n" ); document.write( "hyp * sin 45 = 1
\n" ); document.write( "hyp = 1/(sin 45) = 1/(sqrt(2)/2) = 1/1 * 2/(sqrt(2) = 2/sqrt(2)
\n" ); document.write( "hyp = 1/(sin 45) = 2/sqrt(2) * sqrt(2)/sqrt(2) = 2sqrt(2)/2 = sqrt(2)
\n" ); document.write( "cos 45 = adjacent/hypotenuse = 1/hyp
\n" ); document.write( "45-45-90 triangles are in the ratio 1-1-sqrt(2)
\n" ); document.write( "so each side is the hypotenuse/sqrt(2)
\n" ); document.write( "side length = 28/sqrt(2) = 28sqrt(2)/2 = 14sqrt(2)
\n" ); document.write( "perimeter = 2 * 14sqrt(2) + 28
\n" ); document.write( "perimeter = 28 + 28sqrt(2)
\n" ); document.write( "perimeter = 67.598 to 3 places, 67.6 to one place, 68 to the nearest whole number
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