document.write( "Question 316452: How many gallons of a 25% alcohol solution would need to be mixed with a 35% alcohol solution in order to obtain 20 gallons of a 32% alcohol solutio? \n" ); document.write( "
Algebra.Com's Answer #226437 by Fombitz(32388)\"\" \"About 
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Let A be the amount of 25% solution, B the amount of 35% solution.
\n" ); document.write( "Total quantity equation
\n" ); document.write( "1.\"A%2BB=20\"
\n" ); document.write( "Concentration equation
\n" ); document.write( "\"25A%2B35B=32%2820%29\"
\n" ); document.write( "2.\"25A%2B35B=640\"
\n" ); document.write( "Multiply eq. 1 by -25 and add to eq. 2,
\n" ); document.write( "\"-25A-25B%2B25A%2B35B=-500%2B640\"
\n" ); document.write( "\"10B=140\"
\n" ); document.write( "\"B=14\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"A%2B14=20\"
\n" ); document.write( "\"A=6\"
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\n" ); document.write( "6 gallons of 25% solution and 14 gallons of 35% solution.
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