document.write( "Question 316452: How many gallons of a 25% alcohol solution would need to be mixed with a 35% alcohol solution in order to obtain 20 gallons of a 32% alcohol solutio? \n" ); document.write( "
Algebra.Com's Answer #226437 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Let A be the amount of 25% solution, B the amount of 35% solution. \n" ); document.write( "Total quantity equation \n" ); document.write( "1. \n" ); document.write( "Concentration equation \n" ); document.write( " \n" ); document.write( "2. \n" ); document.write( "Multiply eq. 1 by -25 and add to eq. 2, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then from eq. 1, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "6 gallons of 25% solution and 14 gallons of 35% solution. \n" ); document.write( " \n" ); document.write( " |