document.write( "Question 315541: Suppose that the perimeter of a rectangle is 24 inches and the length is twice the width. What are the dimensions of this rectangle and what is the area? \n" ); document.write( "

Algebra.Com's Answer #226383 by moshiz08(60) $\"\"$ $\"About$

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Perimeter is the sum of the four sides. Since we have a rectangle, opposite sides have the same length. So two of the sides have length L and the other two are the width W. Perimeter is $\"+P+=+2L+%2B+2W+=24+\"$ . \r
\n" ); document.write( "\n" ); document.write( "Length is twice the width, that is $\"+L+=+2+W\"$ . Substitute this into the perimeter equation (replace the 2W with L) to get \r
\n" ); document.write( "\n" ); document.write( " $\"+2L+%2B+2W+=+2L+%2B+L+=+3L+=+24+\"$ . Thus, dividing by 3 gives $\"L+=+8\"$ . The length is twice the width, so the width must be 4. \r
\n" ); document.write( "\n" ); document.write( "We have a 8 x 4 rectangle which has an area of 32 square inches. \r
\n" ); document.write( "\n" ); document.write( "Check that this solution works. The perimeter does indeed add up to 24 and the length is twice the width. \n" ); document.write( "

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