document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=316454>Question 316454</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. y = 2sqrt(x + 3) by graphing 5 points.  Use the endpoint of the function as your first point.<BR>\n" );
document.write( "y = 2 sqrt (x) + 3<BR>\n" );
document.write( "x = 0,         y = 2sqrt(0) + 3 = 3<BR>\n" );
document.write( "x = 1,         y = 2sqrt(1) + 3 = 5<BR>\n" );
document.write( "x = 9,         y = 2sqrt(9) + 3 = 9<BR>\n" );
document.write( "x = 16,        y = 2sqrt(16) + 3 = 11<BR>\n" );
document.write( "x = 25,        y = 2sqrt(25) + 3 = 13\r<BR>\n" );
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document.write( "How do I find out what the endpoint is exactly ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226372 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the graph \"ends\" at x=-3 because the square roots of negative values are not real numbers\r<BR>\n" );
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document.write( "your first point should be x=-3 and go up from there </SPAN>\n" );
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