document.write( "Question 315490: 4+3x-6=3x+2-x \n" ); document.write( "
Algebra.Com's Answer #226371 by moshiz08(60)\"\" \"About 
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\"4%2B3x-6=3x%2B2-x\" \r
\n" ); document.write( "\n" ); document.write( "Combine like terms on the left hand side 4 and -6 to give \r
\n" ); document.write( "\n" ); document.write( "\"3x-2=3x%2B2-x\" \r
\n" ); document.write( "\n" ); document.write( "Combine like terms on the right hand side 3x and -x to give \r
\n" ); document.write( "\n" ); document.write( "\"3x-2=2x%2B2\" \r
\n" ); document.write( "\n" ); document.write( "Add 2 to both sides to get \r
\n" ); document.write( "\n" ); document.write( "\"3x=2x%2B4\" \r
\n" ); document.write( "\n" ); document.write( "Subtract 2x from both sides to get \r
\n" ); document.write( "\n" ); document.write( "\"x+=++4\" .\r
\n" ); document.write( "\n" ); document.write( "Now we check: On the left hand side we have 4+3x-6 and when x is 4 this becomes 4+3*4-6= 4+12-6 = 10. On the right hand side we have 3x+2-x and when x is 4 this becomes 3*4+2-4=12+2-4=10, so we get 10 on both sides which means the solution x=4 is correct.
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