document.write( "Question 316385: S= -3.5n^2+42n+45. S=number of thousands of dollars of sales in week n.
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document.write( "When do you expect the sales to peak?
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document.write( "What is the largest value for the sales during the week?
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document.write( "During what week do we expect the sales to drop to zero? \n" );
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Algebra.Com's Answer #226369 by nerdybill(7384) You can put this solution on YOUR website! S= -3.5n^2+42n+45. S=number of thousands of dollars of sales in week n. \n" ); document.write( "When do you expect the sales to peak? \n" ); document.write( "vertex gives you the max. \n" ); document.write( "axis of symmetry: \n" ); document.write( "n = -b/(2a) = -42/(2*(-3.5)) = -42/-7 = 6 \n" ); document.write( "It will peak at n=6 or the sixth week \n" ); document.write( ". \n" ); document.write( "What is the largest value for the sales during the week? \n" ); document.write( "S= -3.5n^2+42n+45 \n" ); document.write( "set n=6 \n" ); document.write( "S= -3.5*6^2+42(6)+45 \n" ); document.write( "S= -3.5*36+252+45 \n" ); document.write( "S= -126+252+45 \n" ); document.write( "s= 171 (thousands of dollars) \n" ); document.write( ". \n" ); document.write( "During what week do we expect the sales to drop to zero? \n" ); document.write( "set S = 0 solve for n: \n" ); document.write( "S= -3.5n^2+42n+45 \n" ); document.write( "0= -3.5n^2+42n+45 \n" ); document.write( "Applying the quadratic formula yields: \n" ); document.write( "n = {-0.99, 12.99} \n" ); document.write( "We can toss out the negative answer leaving: \n" ); document.write( "n = 12.99 weeks \n" ); document.write( ". \n" ); document.write( "Detail of quadratic follows: \n" ); document.write( "
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