document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=316289>Question 316289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sinem and Ekin leave the same point driving in opposite direction. Ekin's rate 12km/h more than Sinem's rate. After three hours they are 360km apart. Find the rate of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226306 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "360=(X+X+12)3<BR>\n" );
document.write( "360=(2X-12)3<BR>\n" );
document.write( "360=6X-36<BR>\n" );
document.write( "6X=360+36<BR>\n" );
document.write( "6X=324<BR>\n" );
document.write( "X=324/6<BR>\n" );
document.write( "X=54 km/h is Sinem's rate<BR>\n" );
document.write( "54+12=66km/h is Ekin's rate.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "360=(54+66)3<BR>\n" );
document.write( "360=120*3<BR>\n" );
document.write( "360=360<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );