document.write( "Question 316382: f(x)=5x^3+5x^2-x+C
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\n" ); document.write( "Find C
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Algebra.Com's Answer #226299 by jim_thompson5910(35256)\"\" \"About 
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Since f(3)=1, this means that if we plug in x=3, we'll get f(x)=1.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=5x%5E3%2B5x%5E2-x%2BC\" Start with the given function.\r
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\n" ); document.write( "\n" ); document.write( "\"f%283%29=5%283%29%5E3%2B5%283%29%5E2-3%2BC\" Plug in \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"1=5%283%29%5E3%2B5%283%29%5E2-3%2BC\" Plug in \"f%283%29=1\". Our goal is to now solve for C.\r
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\n" ); document.write( "\n" ); document.write( "\"1=5%2827%29%2B5%283%29%5E2-3%2BC\" Cube 3 to get 27\r
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\n" ); document.write( "\n" ); document.write( "\"1=5%2827%29%2B5%289%29-3%2BC\" Square 3 to get 9\r
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\n" ); document.write( "\n" ); document.write( "\"1=135%2B45-3%2BC\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"1=177%2BC\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"1-177=C\" Subtract 177 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-176=C\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the value of C is \"C=-176\" making the function \"f%28x%29=5x%5E3%2B5x%5E2-x-176\"
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