document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=316155>Question 316155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help. I am still stumped. A rectangle has a perimeter of 82 inches with a diagonal of 29 inches. What is the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226268 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226268\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a perimeter of 82 inches with a diagonal of 29 inches.<BR>\n" );
document.write( " What is the length and width of the rectangle?<BR>\n" );
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document.write( "Write the perimeter equation<BR>\n" );
document.write( "2L + 2W = 82<BR>\n" );
document.write( "simplify, divide by 2<BR>\n" );
document.write( "L + W = 41<BR>\n" );
document.write( "L = (41-W); we can use this form for substitution<BR>\n" );
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document.write( "Write the pythag equation; a^2 + b^2 = c^2, where a=L, b=W, c=29<BR>\n" );
document.write( "L^2 + W^2 = 29^2<BR>\n" );
document.write( "L^2 + W^2 = 841<BR>\n" );
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document.write( "Substitute (41-W) for L<BR>\n" );
document.write( "(41-W)^2 + W^2 = 841<BR>\n" );
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document.write( "FOIL (41-W)(41-W)<BR>\n" );
document.write( "(1681 - 41W - 41W + W^2) + W^2 = 841<BR>\n" );
document.write( "1681 - 82W + W^2 + w^2 = 841<BR>\n" );
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document.write( "Arrange as a quadratic equation on the left:<BR>\n" );
document.write( "2W^2 - 82W + 1681 - 841 = 0<BR>\n" );
document.write( "2W^2 - 82W + 840 = 0<BR>\n" );
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document.write( "Simplify, divide by 2<BR>\n" );
document.write( "W^2 - 41W + 420 = 0<BR>\n" );
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document.write( "Factor<BR>\n" );
document.write( "(W-20)(W-21) = 0<BR>\n" );
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document.write( "Two solutions<BR>\n" );
document.write( "W = 20<BR>\n" );
document.write( "and <BR>\n" );
document.write( "W = 21<BR>\n" );
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document.write( "Find the Length when W=20<BR>\n" );
document.write( "L = 41-W<BR>\n" );
document.write( "L = 41-20<BR>\n" );
document.write( "L = 21<BR>\n" );
document.write( "and<BR>\n" );
document.write( "Find the Length when W=21<BR>\n" );
document.write( "L = 41-W<BR>\n" );
document.write( "L = 41-21<BR>\n" );
document.write( "L = 20<BR>\n" );
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document.write( "See if that checks out, find the diagonal (hypotenuse)<BR>\n" );
document.write( "d = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2821%5E2+-+20%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%2821%5E2+-+20%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "d = 29 is the diagonal<BR>\n" );
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document.write( "YOu can confirm the solutions in the perimeter equation </SPAN>\n" );
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