document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=316291>Question 316291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The sum of the measure of the first aqngle and one-fourth the second is 75 degrees.Find the measuresof the angles. What is the measureof the smaller angle and the other angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #226221 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=226221\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The sum of the measure of the first aqngle and one-fourth the second is 75 degrees.Find the measuresof the angles. What is the measureof the smaller angle and the other angle<BR>\n" );
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document.write( "Two angles are complementary if the sum is 90.<BR>\n" );
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document.write( "Let x = first angle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "90-x = second angle<BR>\n" );
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document.write( "x + (1/4)(90-x) = 75<BR>\n" );
document.write( "4x + (90-x) = 300<BR>\n" );
document.write( "3x + 90 = 300<BR>\n" );
document.write( "3x = 210<BR>\n" );
document.write( "x = 70<BR>\n" );
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document.write( "second angle:<BR>\n" );
document.write( "90-x = 90-70 = 20<BR>\n" );
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document.write( "The measeasure of the two angles are<BR>\n" );
document.write( "20 degs and 70 degs<BR>\n" );
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