document.write( "Question 316270: Find the distance between (-2,-3) and (-5,1) \n" ); document.write( "
Algebra.Com's Answer #226212 by jim_thompson5910(35256)\"\" \"About 
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Note: is the first point . So this means that \"x%5B1%5D=-2\" and \"y%5B1%5D=-3\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=-5\" and \"y%5B2%5D=1\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-2--5%29%5E2%2B%28-3-1%29%5E2%29\" Plug in \"x%5B1%5D=-2\", \"x%5B2%5D=-5\", \"y%5B1%5D=-3\", and \"y%5B2%5D=1\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%283%29%5E2%2B%28-3-1%29%5E2%29\" Subtract \"-5\" from \"-2\" to get \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%283%29%5E2%2B%28-4%29%5E2%29\" Subtract \"1\" from \"-3\" to get \"-4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%289%2B%28-4%29%5E2%29\" Square \"3\" to get \"9\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%289%2B16%29\" Square \"-4\" to get \"16\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2825%29\" Add \"9\" to \"16\" to get \"25\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=5\" Take the square root of \"25\" to get \"5\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=5\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points is 5 units. \r
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