document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36833>Question 36833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a number is decreased by its square, the result is 2 over 9. find the number.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22621 by </B><A HREF=/tutors/aboutme.mpl?userid=vidhyak><B>vidhyak(98)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vidhyak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be x<BR>\n" );
document.write( "and the square of the number be x^2\r<BR>\n" );
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document.write( "x- x^2 = 2/9<BR>\n" );
document.write( "Multiply by 9 on both sides<BR>\n" );
document.write( "9x- 9x^2 = 2<BR>\n" );
document.write( "9x- 9x^2 - 2 = 0<BR>\n" );
document.write( "-9x^2 +9x -2 = 0<BR>\n" );
document.write( "Multiply by a -1 on both sides<BR>\n" );
document.write( "9x^2 -9x +2 = 0<BR>\n" );
document.write( "9x^2 -6x - 3x +2 = 0<BR>\n" );
document.write( "3x(3x-2) -1(3x - 2) = 0<BR>\n" );
document.write( "(3x -1 )(3x - 2) = 0\r<BR>\n" );
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document.write( "X = 1/3, 2/3\r<BR>\n" );
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document.write( "Verify the results\r<BR>\n" );
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document.write( "x  - x^2 <BR>\n" );
document.write( "1/3 - (1/3)^2<BR>\n" );
document.write( "1/3 - 1/9\r<BR>\n" );
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document.write( "3-1<BR>\n" );
document.write( "----<BR>\n" );
document.write( "9\r<BR>\n" );
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document.write( "= 2/9\r<BR>\n" );
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document.write( "x  - x^2 <BR>\n" );
document.write( "2/3 - (2/3)^2<BR>\n" );
document.write( "2/3 - 4/9\r<BR>\n" );
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document.write( "6-4<BR>\n" );
document.write( "----<BR>\n" );
document.write( "9\r<BR>\n" );
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document.write( "= 2/9 </SPAN>\n" );
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