document.write( "Question 315423: Yoshi +12 years = her sister's age.
\n" ); document.write( "6 years from now the sum of their ages will equal 32.
\n" ); document.write( "What is Yoshi's present age?
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Algebra.Com's Answer #226205 by moshiz08(60)\"\" \"About 
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We have the first equation \"Y+%2B+12+=+S\" (where Y = yoshi's age, S = her sister's age) \r
\n" ); document.write( "\n" ); document.write( "For the second equation (6 years from now the sum of their ages will equal 32): six years from now we know that Yoshi's age will be Y+6. Her sister's age will be S+6. Thus the equation reads:
\n" ); document.write( "\"%28Y%2B6%29+%2B+%28S%2B6%29+=+32\". This is the same as combining like terms to give \"Y+%2B+S+%2B+12+=+32\" or subtracting 12 from both sides to give \"Y+%2B+S+=+20\". \r
\n" ); document.write( "\n" ); document.write( "But we know from the first equation that \"S+=+Y+%2B+12\". Substitute this into \"Y+%2B+S+=+20\" to give \"Y+%2B+%28Y%2B12%29+=+20\". Then combining like terms gives \"2Y+%2B+12+=+20\". Subtracting 12 from both sides gives \"2Y+=+8\". Dividing by 2 yields \"Y+=+4\". \r
\n" ); document.write( "\n" ); document.write( "Now we check. If yoshi is 4 years old, then his sister is 4+12 = 16 years old.
\n" ); document.write( "In six years, yoshi will be 10. His sister will be 22. The sum of their ages (10 + 22) gives us 32, so the answer yoshi is 4 works.
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